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#1
September 30, 2008, 05:14:10 PM
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throw new Bomb("you");
Look at this funny Java code:
Main.java Code:
/*
* Main.java
* Bomb - this is just a working joke code.
*/
package bomb;
/**
* @author jirachifan
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws Bomb
{
try
{
throw new Bomb("you");
}
catch(Bomb the_Bomb)
{
the_Bomb.Explode();
}
}
}
Code:
/*
* Bomb.java
*/
package bomb;
/**
*
* @author jirachifan
*/
public class Bomb extends Exception
{
private String Target;
public Bomb(String theTarget)
{
System.out.println("The bomb was thrown to " + theTarget + ".\n");
Target = theTarget;
}
public void Explode()
{
System.out.println("BOOM!!\n");
if (Target.toString() == "you")
{
System.out.printf("%s are dead now.\n", Target);
}
else
{
System.out.printf("%s is dead now.\n", Target);
}
}
}
Code:
The bomb was thrown to you. BOOM!! you are dead now. |
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#2
October 1, 2008, 01:03:40 PM
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Re: throw new Bomb("you");
LOL. I always thought of throwing and catching a ball, but a bomb works also.
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#3
October 1, 2008, 06:41:15 PM
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Re: throw new Bomb("you");
Go
BOOM |
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#4
October 2, 2008, 03:26:12 PM
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Re: throw new Bomb("you");
It reminds me of one of the Duel mini-games in...was it Mario Party 2? You had to pass a Bob-Omb around. If it exploded, you were out.
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#5
October 2, 2008, 03:29:24 PM
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Re: throw new Bomb("you");
Quote:
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